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Example 1: Calculate the area of the regular hexagon with a side length of 6m.

Since it’s a regular hexagon, all the sides are equal to each other.

Hence from the center, 6 congruent equilateral triangles are formed.

Given the side length of the hexagon, s = 3m

Area of an equilateral triangle = √3/4 * s2 where s = side length

Hence area of the regular hexagon, A = 6 * (Area of the equilateral triangle)

Area of regular hexagon, A = 6 * √3/4 * s2 = √3/4 * (6)2 = 15.6m2

**Example 2: Calculate the area of the regularhexagon with a side length of 12m.**

Since it’s a regular hexagon, all the sides are equal to each other.

Hence from the center, 6 congruent equilateral triangles are formed.

Given the side length of the hexagon, s = 12m

**Area of an equilateral triangle = √3/4 * s**^{2} where s = side length

**Hence area of the regular hexagon, A = 6 * (Area of the equilateral triangle)**

Area of regular hexagon,**A = 6 * √3/4 * s**^{2} = √3/4 * (12)^{2} = **62.35m**^{2}

Since it’s a regular hexagon, all the sides are equal to each other.

Hence from the center, 6 congruent equilateral triangles are formed.

Given the side length of the hexagon, s = 12m

Area of regular hexagon,