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A regular hexagon has 6 sides of equal length.

Hence it can have 6 equilateral triangles with each angle of

the triangle equal to = 60°

Apothem in the regular hexagon as shown is = AD

The apothem of the polygon divides the angle into half = 30°

Now the entire side length, BC = 10m and DC = 5m

In triangle ADC, tan30° = DC/AD = 5/AD

Apothem, AD = 5/tan30° = 8.66m

**Example 2: In the above given regular hexagon, find the area of the hexagon using the length of the apothem.**

Area of one triangle in a regular hexagon =1/2 * base * apothem

Given above, base length = side length, BC = 10m

Apothem calculated above, AD = 8.66m

**Hence area of the triangle, ABC = 1/2 * BC * AD** = 1/2 * 10 * 8.66

So are of the triangle, ABC = 43.3m^{2}

There are total 6 equal triangles in the given hexagon.

**Hence area of the regular hexagon = 6 * 43.3 = 259.8m**^{2}

Area of one triangle in a regular hexagon =1/2 * base * apothem

Given above, base length = side length, BC = 10m

Apothem calculated above, AD = 8.66m

So are of the triangle, ABC = 43.3m

There are total 6 equal triangles in the given hexagon.